7x^2+240x-7200=0

Solution for 7x^2+240x-7200=0 equation:

7x^2+240x-7200=0

a = 7; b = 240; c = -7200;
Δ = b2-4ac
Δ = 2402-4·7·(-7200)
Δ = 259200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{259200}=\sqrt{129600*2}=\sqrt{129600}*\sqrt{2}=360\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-360\sqrt{2}}{2*7}=\frac{-240-360\sqrt{2}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+360\sqrt{2}}{2*7}=\frac{-240+360\sqrt{2}}{14}
$